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Old 11-16-2009, 11:39 PM   #1 (permalink)
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Default Help me show my work for my chemistry problems..did them but no work...[reputation]

I don't have anything else to offer at this time except reputation to the ones who can help me show the work for any of these problems...im sick of the teacher i did it all on my graphic calculator but noo i need the work...i got the answers though.

Using average atomic mass for each of the following elements. calculate the number of atoms present in each of the following samples...

a. 10.81 amu of boron - answer is 1
b. 320.7 amu of sulfur - answer is 10
c. 19,697 amu of gold - answer is 100
d. 19,695 amu of xenon - answer is 150
e. 3588.3 amu of aluminum - answer is 133

in 24.02 g of carbon there are __ carb on atoms... answer is 1.25x10^24

what mass of cobalt contains the same number of atoms as 57.0 g of fluorine? i got 177 grams...help me show work

calculate the average mass in grams of 1 atom of oxygen

I got 2.66x10^-23

Thanks all i need is the work if possible..
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Old 11-17-2009, 12:14 AM   #2 (permalink)
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a) 10.81 amu B * (1 atom B/10.81amu B) = 1 Atom B
b) 320.7 amu Sulfur * (1 atom S/32.07amu S) = 10 Atoms S
c) 19,697 amu Au * (1 atom Au/196.97amu Au) = 100 Atoms Au
d) 19,695 amu Xe * (1 atom Xe/131.3amu Xe) = 150 Atoms Xe
e) 3588.3 amu Al * (1 atom Al/26.98amu Al) = 133 Atoms Al

in 24.02 g of carbon there are __ carb on atoms... answer is 1.25x10^24

24.02g C * (1 mole C/12.011g) * ((6.022*10^23)/1mole C) = 1.204 * 10^24 Atoms (my answer is different from yours...no idea why)

what mass of cobalt contains the same number of atoms as 57.0 g of fluorine? i got 177 grams...help me show work

57g F * (1 mole F/19g F) * ((6.022*10^23atoms)/1mole F) = 1.8066 * 10^24 Atoms
1.8066*10^24 Atoms * (1mole Co/(6.022*10^23Atoms)) * (58.93g Co/1mole Co) = 176.79g Co

calculate the average mass in grams of 1 atom of oxygen

1 Atom O * (1mole O/(6.022*10^23Atoms O) * (16g O/1mole O) = 2.657*10^-23 g O
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Old 11-17-2009, 12:16 AM   #3 (permalink)
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EDIT: nvm, iluvchina just owned me. I got the same answer for the 2nd problem as you did too.

Also wtf, how do you do it without showing work? Seriously, you can't rely on your calculator for everything. answers.yahoo.com is an amazing homework help site too.

Last edited by sibble; 11-17-2009 at 12:22 AM..
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Old 11-17-2009, 12:30 AM   #4 (permalink)
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Hey willylove I received your message but I can't send a pm back since that was my first post. I am pretty sure you can post the rest of the problems and someone like sibble might be able to help you out.
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Old 11-17-2009, 12:31 AM   #5 (permalink)
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Quote:
Originally Posted by iluvchina View Post
a) 10.81 amu B * (1 atom B/10.81amu B) = 1 Atom B
b) 320.7 amu Sulfur * (1 atom S/32.07amu S) = 10 Atoms S
c) 19,697 amu Au * (1 atom Au/196.97amu Au) = 100 Atoms Au
d) 19,695 amu Xe * (1 atom Xe/131.3amu Xe) = 150 Atoms Xe
e) 3588.3 amu Al * (1 atom Al/26.98amu Al) = 133 Atoms Al

in 24.02 g of carbon there are __ carb on atoms... answer is 1.25x10^24

24.02g C * (1 mole C/12.011g) * ((6.022*10^23)/1mole C) = 1.204 * 10^24 Atoms (my answer is different from yours...no idea why)

what mass of cobalt contains the same number of atoms as 57.0 g of fluorine? i got 177 grams...help me show work

57g F * (1 mole F/19g F) * ((6.022*10^23atoms)/1mole F) = 1.8066 * 10^24 Atoms
1.8066*10^24 Atoms * (1mole Co/(6.022*10^23Atoms)) * (58.93g Co/1mole Co) = 176.79g Co

calculate the average mass in grams of 1 atom of oxygen

1 Atom O * (1mole O/(6.022*10^23Atoms O) * (16g O/1mole O) = 2.657*10^-23 g O
lol, you just got tricked into doing his homework for him. He ALWAYS ask for homework help and makes false promises of paying ppl.

he probably got the answers in the back of the book and still didnt know how to solve the problem LOL...
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Old 11-17-2009, 12:34 AM   #6 (permalink)
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Oh well. I didn't expect to get paid anyways. And he just offered to paypal me if I did more. ~_~
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Old 11-17-2009, 12:36 AM   #7 (permalink)
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i didnt pay $120 for nothing for this darn calculator..
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